X^2+20x/3=0

Solution for X^2+20x/3=0 equation:

X^2+20X/3=0

We multiply all the terms by the denominator


X^2*3+20X=0

Wy multiply elements

3X^2+20X=0

a = 3; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·3·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*3}=\frac{-40}{6}
=-6+2/3
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*3}=\frac{0}{6}
=0
$